Metamath Proof Explorer


Theorem coshcl

Description: The closure of the cosh function with complex argument. (Contributed by Jon Pennant, 9-Sep-2026)

Ref Expression
Assertion coshcl ( 𝐴 ∈ ℂ → ( cosh ‘ 𝐴 ) ∈ ℂ )

Proof

Step Hyp Ref Expression
1 coshf ⊢ cosh : ℂ ⟶ ℂ
2 1 ffvelcdmi ⊢ ( 𝐴 ∈ ℂ → ( cosh ‘ 𝐴 ) ∈ ℂ )