Metamath Proof Explorer


Theorem crngprmringidom

Description: A commutative ring is a prime ring if and only if it is an integral domain. (Contributed by AV, 27-Jun-2026)

Ref Expression
Assertion crngprmringidom ( 𝑅 ∈ CRing → ( 𝑅 ∈ PrmRing ↔ 𝑅 ∈ IDomn ) )

Proof

Step Hyp Ref Expression
1 crngring ( 𝑅 ∈ CRing → 𝑅 ∈ Ring )
2 eqid ( 0g𝑅 ) = ( 0g𝑅 )
3 eqid ( PrmIdeal ‘ 𝑅 ) = ( PrmIdeal ‘ 𝑅 )
4 2 3 isprmrng ( 𝑅 ∈ PrmRing ↔ ( 𝑅 ∈ Ring ∧ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) )
5 4 a1i ( 𝑅 ∈ CRing → ( 𝑅 ∈ PrmRing ↔ ( 𝑅 ∈ Ring ∧ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) ) )
6 1 5 mpbirand ( 𝑅 ∈ CRing → ( 𝑅 ∈ PrmRing ↔ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) )
7 ibar ( 𝑅 ∈ CRing → ( { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ↔ ( 𝑅 ∈ CRing ∧ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) ) )
8 2 prmidl0 ( ( 𝑅 ∈ CRing ∧ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) ↔ 𝑅 ∈ IDomn )
9 8 a1i ( 𝑅 ∈ CRing → ( ( 𝑅 ∈ CRing ∧ { ( 0g𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) ↔ 𝑅 ∈ IDomn ) )
10 6 7 9 3bitrd ( 𝑅 ∈ CRing → ( 𝑅 ∈ PrmRing ↔ 𝑅 ∈ IDomn ) )