Metamath Proof Explorer


Theorem difeq2d

Description: Deduction adding difference to the left in a class equality. (Contributed by NM, 15-Nov-2002)

Ref Expression
Hypothesis difeq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion difeq2d ( 𝜑 → ( 𝐶 ∖ 𝐴 ) = ( 𝐶 ∖ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 difeq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 difeq2 ⊢ ( 𝐴 = 𝐵 → ( 𝐶 ∖ 𝐴 ) = ( 𝐶 ∖ 𝐵 ) )
3 1 2 syl ⊢ ( 𝜑 → ( 𝐶 ∖ 𝐴 ) = ( 𝐶 ∖ 𝐵 ) )