Metamath Proof Explorer


Theorem disjr

Description: Two ways of saying that two classes are disjoint. (Contributed by Jeff Madsen, 19-Jun-2011)

Ref Expression
Assertion disjr ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )

Proof

Step Hyp Ref Expression
1 ineqcom ( ( 𝐴𝐵 ) = ∅ ↔ ( 𝐵𝐴 ) = ∅ )
2 disj ( ( 𝐵𝐴 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )
3 1 2 bitri ( ( 𝐴𝐵 ) = ∅ ↔ ∀ 𝑥𝐵 ¬ 𝑥𝐴 )