Metamath Proof Explorer


Theorem edgfndx

Description: Index value of the df-edgf slot. (Contributed by AV, 13-Oct-2024) (New usage is discouraged.)

Ref Expression
Assertion edgfndx ( .ef ‘ ndx ) = 1 8

Proof

Step Hyp Ref Expression
1 df-edgf .ef = Slot 1 8
2 1nn0 1 ∈ ℕ0
3 8nn 8 ∈ ℕ
4 2 3 decnncl 1 8 ∈ ℕ
5 1 4 ndxarg ( .ef ‘ ndx ) = 1 8