Metamath Proof Explorer


Theorem elelsuc

Description: Membership in a successor. (Contributed by NM, 20-Jun-1998)

Ref Expression
Assertion elelsuc ( 𝐴𝐵𝐴 ∈ suc 𝐵 )

Proof

Step Hyp Ref Expression
1 orc ( 𝐴𝐵 → ( 𝐴𝐵𝐴 = 𝐵 ) )
2 elsucg ( 𝐴𝐵 → ( 𝐴 ∈ suc 𝐵 ↔ ( 𝐴𝐵𝐴 = 𝐵 ) ) )
3 1 2 mpbird ( 𝐴𝐵𝐴 ∈ suc 𝐵 )