Metamath Proof Explorer


Theorem elelsuc

Description: Membership in a successor. (Contributed by NM, 20-Jun-1998)

Ref Expression
Assertion elelsuc ( 𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵 )

Proof

Step Hyp Ref Expression
1 orc ⊢ ( 𝐴 ∈ 𝐵 → ( 𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵 ) )
2 elsucg ⊢ ( 𝐴 ∈ 𝐵 → ( 𝐴 ∈ suc 𝐵 ↔ ( 𝐴 ∈ 𝐵 ∨ 𝐴 = 𝐵 ) ) )
3 1 2 mpbird ⊢ ( 𝐴 ∈ 𝐵 → 𝐴 ∈ suc 𝐵 )