Metamath Proof Explorer


Theorem elint

Description: Membership in class intersection. (Contributed by NM, 21-May-1994)

Ref Expression
Hypothesis elint.1 ⊢ 𝐴 ∈ V
Assertion elint ( 𝐴 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐵 → 𝐴 ∈ 𝑥 ) )

Proof

Step Hyp Ref Expression
1 elint.1 ⊢ 𝐴 ∈ V
2 eleq1 ⊢ ( 𝑦 = 𝐴 → ( 𝑦 ∈ 𝑥 ↔ 𝐴 ∈ 𝑥 ) )
3 2 imbi2d ⊢ ( 𝑦 = 𝐴 → ( ( 𝑥 ∈ 𝐵 → 𝑦 ∈ 𝑥 ) ↔ ( 𝑥 ∈ 𝐵 → 𝐴 ∈ 𝑥 ) ) )
4 3 albidv ⊢ ( 𝑦 = 𝐴 → ( ∀ 𝑥 ( 𝑥 ∈ 𝐵 → 𝑦 ∈ 𝑥 ) ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐵 → 𝐴 ∈ 𝑥 ) ) )
5 df-int ⊢ ∩ 𝐵 = { 𝑦 ∣ ∀ 𝑥 ( 𝑥 ∈ 𝐵 → 𝑦 ∈ 𝑥 ) }
6 1 4 5 elab2 ⊢ ( 𝐴 ∈ ∩ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐵 → 𝐴 ∈ 𝑥 ) )