Metamath Proof Explorer


Theorem elpm2

Description: The predicate "is a partial function." (Contributed by NM, 15-Nov-2007) (Revised by Mario Carneiro, 31-Dec-2013)

Ref Expression
Hypotheses elmap.1 𝐴 ∈ V
elmap.2 𝐵 ∈ V
Assertion elpm2 ( 𝐹 ∈ ( 𝐴pm 𝐵 ) ↔ ( 𝐹 : dom 𝐹𝐴 ∧ dom 𝐹𝐵 ) )

Proof

Step Hyp Ref Expression
1 elmap.1 𝐴 ∈ V
2 elmap.2 𝐵 ∈ V
3 elpm2g ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) → ( 𝐹 ∈ ( 𝐴pm 𝐵 ) ↔ ( 𝐹 : dom 𝐹𝐴 ∧ dom 𝐹𝐵 ) ) )
4 1 2 3 mp2an ( 𝐹 ∈ ( 𝐴pm 𝐵 ) ↔ ( 𝐹 : dom 𝐹𝐴 ∧ dom 𝐹𝐵 ) )