Metamath Proof Explorer


Theorem epnsym

Description: The membership (epsilon) relation is not symmetric. (Contributed by AV, 18-Jun-2022)

Ref Expression
Assertion epnsym ◡ E ≠ E

Proof

Step Hyp Ref Expression
1 cnvepnep ⊢ ( ◡ E ∩ E ) = ∅
2 disjeq0 ⊢ ( ( ◡ E ∩ E ) = ∅ → ( ◡ E = E ↔ ( ◡ E = ∅ ∧ E = ∅ ) ) )
3 epn0 ⊢ E ≠ ∅
4 eqneqall ⊢ ( E = ∅ → ( E ≠ ∅ → ◡ E ≠ E ) )
5 3 4 mpi ⊢ ( E = ∅ → ◡ E ≠ E )
6 5 adantl ⊢ ( ( ◡ E = ∅ ∧ E = ∅ ) → ◡ E ≠ E )
7 6 a1i ⊢ ( ◡ E = E → ( ( ◡ E = ∅ ∧ E = ∅ ) → ◡ E ≠ E ) )
8 neqne ⊢ ( ¬ ◡ E = E → ◡ E ≠ E )
9 8 a1d ⊢ ( ¬ ◡ E = E → ( ¬ ( ◡ E = ∅ ∧ E = ∅ ) → ◡ E ≠ E ) )
10 7 9 bija ⊢ ( ( ◡ E = E ↔ ( ◡ E = ∅ ∧ E = ∅ ) ) → ◡ E ≠ E )
11 1 2 10 mp2b ⊢ ◡ E ≠ E