Metamath Proof Explorer


Theorem eqeq12

Description: Equality relationship among four classes. (Contributed by NM, 3-Aug-1994) (Proof shortened by Wolf Lammen, 23-Oct-2024)

Ref Expression
Assertion eqeq12 ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )

Proof

Step Hyp Ref Expression
1 id ⊢ ( 𝐴 = 𝐵 → 𝐴 = 𝐵 )
2 id ⊢ ( 𝐶 = 𝐷 → 𝐶 = 𝐷 )
3 1 2 eqeqan12d ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 = 𝐶 ↔ 𝐵 = 𝐷 ) )