Metamath Proof Explorer


Theorem eqtr4id

Description: An equality transitivity deduction. (Contributed by NM, 29-Mar-1998)

Ref Expression
Hypotheses eqtr4id.2 ⊢ 𝐴 = 𝐵
eqtr4id.1 ⊢ ( 𝜑 → 𝐶 = 𝐵 )
Assertion eqtr4id ( 𝜑 → 𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 eqtr4id.2 ⊢ 𝐴 = 𝐵
2 eqtr4id.1 ⊢ ( 𝜑 → 𝐶 = 𝐵 )
3 1 eqcomi ⊢ 𝐵 = 𝐴
4 2 3 eqtr2di ⊢ ( 𝜑 → 𝐴 = 𝐶 )