Metamath Proof Explorer


Theorem equcomi1

Description: Proof of equcomi from equid1 , avoiding use of ax-5 (the only use of ax-5 is via ax7 , so using ax-7 instead would remove dependency on ax-5 ). (Contributed by BJ, 8-Jul-2021) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion equcomi1 ( 𝑥 = 𝑦𝑦 = 𝑥 )

Proof

Step Hyp Ref Expression
1 equid1 𝑥 = 𝑥
2 ax7 ( 𝑥 = 𝑦 → ( 𝑥 = 𝑥𝑦 = 𝑥 ) )
3 1 2 mpi ( 𝑥 = 𝑦𝑦 = 𝑥 )