Metamath Proof Explorer


Theorem equequ2

Description: An equivalence law for equality. (Contributed by NM, 21-Jun-1993) (Proof shortened by Wolf Lammen, 4-Aug-2017) (Proof shortened by BJ, 12-Apr-2021)

Ref Expression
Assertion equequ2 ( 𝑥 = 𝑦 → ( 𝑧 = 𝑥 ↔ 𝑧 = 𝑦 ) )

Proof

Step Hyp Ref Expression
1 equtrr ⊢ ( 𝑥 = 𝑦 → ( 𝑧 = 𝑥 → 𝑧 = 𝑦 ) )
2 equeuclr ⊢ ( 𝑥 = 𝑦 → ( 𝑧 = 𝑦 → 𝑧 = 𝑥 ) )
3 1 2 impbid ⊢ ( 𝑥 = 𝑦 → ( 𝑧 = 𝑥 ↔ 𝑧 = 𝑦 ) )