Metamath Proof Explorer


Theorem ezsubrg

Description: The Eisenstein integers form a subring of the complex numbers. (Contributed by AV, 26-Oct-2026)

Ref Expression
Assertion ezsubrg ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∈ ( SubRing ‘ ℂfld )

Proof

Step Hyp Ref Expression
1 3nn ⊢ 3 ∈ ℕ
2 brucn ⊢ ( 3 ∈ ℕ → ( bRoU ‘ 3 ) ∈ ℂ )
3 1 2 ax-mp ⊢ ( bRoU ‘ 3 ) ∈ ℂ
4 lazcn ⊢ ( ( bRoU ‘ 3 ) ∈ ℂ → ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) → 𝑎 ∈ ℂ ) )
5 3 4 ax-mp ⊢ ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) → 𝑎 ∈ ℂ )
6 eqid ⊢ ( Z[]l ‘ ( bRoU ‘ 3 ) ) = ( Z[]l ‘ ( bRoU ‘ 3 ) )
7 6 lazaddcl ⊢ ( ( bRoU ‘ 3 ) ∈ ℂ → ( ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∧ 𝑏 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) → ( 𝑎 + 𝑏 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) )
8 3 7 ax-mp ⊢ ( ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∧ 𝑏 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) → ( 𝑎 + 𝑏 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) )
9 6 laznegcl ⊢ ( ( bRoU ‘ 3 ) ∈ ℂ → ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) → - 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) )
10 3 9 ax-mp ⊢ ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) → - 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) )
11 1z ⊢ 1 ∈ ℤ
12 zellaz ⊢ ( ( ( bRoU ‘ 3 ) ∈ ℂ ∧ 1 ∈ ℤ ) → 1 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) )
13 3 11 12 mp2an ⊢ 1 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) )
14 bru3sqez ⊢ ( ( bRoU ‘ 3 ) ↑ 2 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) )
15 6 lazmulcl ⊢ ( ( ( bRoU ‘ 3 ) ∈ ℂ ∧ ( ( bRoU ‘ 3 ) ↑ 2 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) → ( ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∧ 𝑏 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) → ( 𝑎 · 𝑏 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) )
16 3 14 15 mp2an ⊢ ( ( 𝑎 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∧ 𝑏 ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ) → ( 𝑎 · 𝑏 ) ∈ ( Z[]l ‘ ( bRoU ‘ 3 ) ) )
17 5 8 10 13 16 cnsubrglem ⊢ ( Z[]l ‘ ( bRoU ‘ 3 ) ) ∈ ( SubRing ‘ ℂfld )