Metamath Proof Explorer


Theorem fac3

Description: The factorial of 3. (Contributed by NM, 17-Mar-2005)

Ref Expression
Assertion fac3 ( ! ‘ 3 ) = 6

Proof

Step Hyp Ref Expression
1 df-3 3 = ( 2 + 1 )
2 1 fveq2i ( ! ‘ 3 ) = ( ! ‘ ( 2 + 1 ) )
3 2nn0 2 ∈ ℕ0
4 facp1 ( 2 ∈ ℕ0 → ( ! ‘ ( 2 + 1 ) ) = ( ( ! ‘ 2 ) · ( 2 + 1 ) ) )
5 3 4 ax-mp ( ! ‘ ( 2 + 1 ) ) = ( ( ! ‘ 2 ) · ( 2 + 1 ) )
6 fac2 ( ! ‘ 2 ) = 2
7 2p1e3 ( 2 + 1 ) = 3
8 6 7 oveq12i ( ( ! ‘ 2 ) · ( 2 + 1 ) ) = ( 2 · 3 )
9 2t3e6 ( 2 · 3 ) = 6
10 8 9 eqtri ( ( ! ‘ 2 ) · ( 2 + 1 ) ) = 6
11 2 5 10 3eqtri ( ! ‘ 3 ) = 6