Metamath Proof Explorer


Theorem fdmd

Description: Deduction form of fdm . The domain of a mapping. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis fdmd.1 ( 𝜑𝐹 : 𝐴𝐵 )
Assertion fdmd ( 𝜑 → dom 𝐹 = 𝐴 )

Proof

Step Hyp Ref Expression
1 fdmd.1 ( 𝜑𝐹 : 𝐴𝐵 )
2 fdm ( 𝐹 : 𝐴𝐵 → dom 𝐹 = 𝐴 )
3 1 2 syl ( 𝜑 → dom 𝐹 = 𝐴 )