Metamath Proof Explorer


Theorem feq23i

Description: Equality inference for functions. (Contributed by Paul Chapman, 22-Jun-2011)

Ref Expression
Hypotheses feq23i.1 ⊢ 𝐴 = 𝐶
feq23i.2 ⊢ 𝐵 = 𝐷
Assertion feq23i ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐹 : 𝐶 ⟶ 𝐷 )

Proof

Step Hyp Ref Expression
1 feq23i.1 ⊢ 𝐴 = 𝐶
2 feq23i.2 ⊢ 𝐵 = 𝐷
3 feq23 ⊢ ( ( 𝐴 = 𝐶 ∧ 𝐵 = 𝐷 ) → ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐹 : 𝐶 ⟶ 𝐷 ) )
4 1 2 3 mp2an ⊢ ( 𝐹 : 𝐴 ⟶ 𝐵 ↔ 𝐹 : 𝐶 ⟶ 𝐷 )