Metamath Proof Explorer


Theorem feq23i

Description: Equality inference for functions. (Contributed by Paul Chapman, 22-Jun-2011)

Ref Expression
Hypotheses feq23i.1 𝐴 = 𝐶
feq23i.2 𝐵 = 𝐷
Assertion feq23i ( 𝐹 : 𝐴𝐵𝐹 : 𝐶𝐷 )

Proof

Step Hyp Ref Expression
1 feq23i.1 𝐴 = 𝐶
2 feq23i.2 𝐵 = 𝐷
3 feq23 ( ( 𝐴 = 𝐶𝐵 = 𝐷 ) → ( 𝐹 : 𝐴𝐵𝐹 : 𝐶𝐷 ) )
4 1 2 3 mp2an ( 𝐹 : 𝐴𝐵𝐹 : 𝐶𝐷 )