Metamath Proof Explorer


Theorem fneq12

Description: Equality theorem for function predicate with domain. (Contributed by Thierry Arnoux, 31-Jan-2017)

Ref Expression
Assertion fneq12 ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐵 ) → ( 𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵 ) )

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐵 ) → 𝐹 = 𝐺 )
2 simpr ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐵 ) → 𝐴 = 𝐵 )
3 1 2 fneq12d ⊢ ( ( 𝐹 = 𝐺 ∧ 𝐴 = 𝐵 ) → ( 𝐹 Fn 𝐴 ↔ 𝐺 Fn 𝐵 ) )