Metamath Proof Explorer


Theorem grplactfval

Description: The left group action of element A of group G . (Contributed by Paul Chapman, 18-Mar-2008)

Ref Expression
Hypotheses grplact.1 ⊢ 𝐹 = ( 𝑔 ∈ 𝑋 ↦ ( 𝑎 ∈ 𝑋 ↦ ( 𝑔 + 𝑎 ) ) )
grplact.2 ⊢ 𝑋 = ( Base ‘ 𝐺 )
Assertion grplactfval ( 𝐴 ∈ 𝑋 → ( 𝐹 ‘ 𝐴 ) = ( 𝑎 ∈ 𝑋 ↦ ( 𝐴 + 𝑎 ) ) )

Proof

Step Hyp Ref Expression
1 grplact.1 ⊢ 𝐹 = ( 𝑔 ∈ 𝑋 ↦ ( 𝑎 ∈ 𝑋 ↦ ( 𝑔 + 𝑎 ) ) )
2 grplact.2 ⊢ 𝑋 = ( Base ‘ 𝐺 )
3 oveq1 ⊢ ( 𝑔 = 𝐴 → ( 𝑔 + 𝑎 ) = ( 𝐴 + 𝑎 ) )
4 3 mpteq2dv ⊢ ( 𝑔 = 𝐴 → ( 𝑎 ∈ 𝑋 ↦ ( 𝑔 + 𝑎 ) ) = ( 𝑎 ∈ 𝑋 ↦ ( 𝐴 + 𝑎 ) ) )
5 4 1 2 mptfvmpt ⊢ ( 𝐴 ∈ 𝑋 → ( 𝐹 ‘ 𝐴 ) = ( 𝑎 ∈ 𝑋 ↦ ( 𝐴 + 𝑎 ) ) )