Metamath Proof Explorer
Description: Equality law for relations being herditary over a class. (Contributed by RP, 27-Mar-2020)
|
|
Ref |
Expression |
|
Assertion |
heeq2 |
⊢ ( 𝐴 = 𝐵 → ( 𝑅 hereditary 𝐴 ↔ 𝑅 hereditary 𝐵 ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
eqid |
⊢ 𝑅 = 𝑅 |
| 2 |
|
heeq12 |
⊢ ( ( 𝑅 = 𝑅 ∧ 𝐴 = 𝐵 ) → ( 𝑅 hereditary 𝐴 ↔ 𝑅 hereditary 𝐵 ) ) |
| 3 |
1 2
|
mpan |
⊢ ( 𝐴 = 𝐵 → ( 𝑅 hereditary 𝐴 ↔ 𝑅 hereditary 𝐵 ) ) |