Metamath Proof Explorer


Theorem icccntri

Description: Membership in a contracted interval. (Contributed by Jeff Madsen, 2-Sep-2009)

Ref Expression
Hypotheses icccntri.1 𝐴 ∈ ℝ
icccntri.2 𝐵 ∈ ℝ
icccntri.3 𝑅 ∈ ℝ+
icccntri.4 ( 𝐴 / 𝑅 ) = 𝐶
icccntri.5 ( 𝐵 / 𝑅 ) = 𝐷
Assertion icccntri ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) → ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) )

Proof

Step Hyp Ref Expression
1 icccntri.1 𝐴 ∈ ℝ
2 icccntri.2 𝐵 ∈ ℝ
3 icccntri.3 𝑅 ∈ ℝ+
4 icccntri.4 ( 𝐴 / 𝑅 ) = 𝐶
5 icccntri.5 ( 𝐵 / 𝑅 ) = 𝐷
6 iccssre ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ) → ( 𝐴 [,] 𝐵 ) ⊆ ℝ )
7 1 2 6 mp2an ( 𝐴 [,] 𝐵 ) ⊆ ℝ
8 7 sseli ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) → 𝑋 ∈ ℝ )
9 4 5 icccntr ( ( ( 𝐴 ∈ ℝ ∧ 𝐵 ∈ ℝ ) ∧ ( 𝑋 ∈ ℝ ∧ 𝑅 ∈ ℝ+ ) ) → ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) ↔ ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) ) )
10 1 2 9 mpanl12 ( ( 𝑋 ∈ ℝ ∧ 𝑅 ∈ ℝ+ ) → ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) ↔ ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) ) )
11 3 10 mpan2 ( 𝑋 ∈ ℝ → ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) ↔ ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) ) )
12 11 biimpd ( 𝑋 ∈ ℝ → ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) → ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) ) )
13 8 12 mpcom ( 𝑋 ∈ ( 𝐴 [,] 𝐵 ) → ( 𝑋 / 𝑅 ) ∈ ( 𝐶 [,] 𝐷 ) )