Metamath Proof Explorer


Theorem inv1

Description: The intersection of a class with the universal class is itself. Exercise 4.10(k) of Mendelson p. 231. (Contributed by NM, 17-May-1998)

Ref Expression
Assertion inv1 ( 𝐴 ∩ V ) = 𝐴

Proof

Step Hyp Ref Expression
1 inss1 ( 𝐴 ∩ V ) ⊆ 𝐴
2 ssid 𝐴𝐴
3 ssv 𝐴 ⊆ V
4 2 3 ssini 𝐴 ⊆ ( 𝐴 ∩ V )
5 1 4 eqssi ( 𝐴 ∩ V ) = 𝐴