Metamath Proof Explorer


Theorem ltdivmuls2d

Description: Surreal less-than relationship between division and multiplication. (Contributed by Scott Fenton, 16-Mar-2025)

Ref Expression
Hypotheses ltdivmulsd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
ltdivmulsd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
ltdivmulsd.3 ⊢ ( 𝜑 → 𝐶 ∈ No )
ltdivmulsd.4 ⊢ ( 𝜑 → 0s <s 𝐶 )
Assertion ltdivmuls2d ( 𝜑 → ( ( 𝐴 /su 𝐶 ) <s 𝐵 ↔ 𝐴 <s ( 𝐵 ·s 𝐶 ) ) )

Proof

Step Hyp Ref Expression
1 ltdivmulsd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 ltdivmulsd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 ltdivmulsd.3 ⊢ ( 𝜑 → 𝐶 ∈ No )
4 ltdivmulsd.4 ⊢ ( 𝜑 → 0s <s 𝐶 )
5 4 gt0ne0sd ⊢ ( 𝜑 → 𝐶 ≠ 0s )
6 3 5 recsexd ⊢ ( 𝜑 → ∃ 𝑥 ∈ No ( 𝐶 ·s 𝑥 ) = 1s )
7 1 2 3 4 6 ltdivmuls2wd ⊢ ( 𝜑 → ( ( 𝐴 /su 𝐶 ) <s 𝐵 ↔ 𝐴 <s ( 𝐵 ·s 𝐶 ) ) )