Metamath Proof Explorer


Theorem ltsnled

Description: Surreal less-than in terms of less-than or equal. Deduction version. (Contributed by Scott Fenton, 25-Feb-2026)

Ref Expression
Hypotheses lesd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
lesd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
Assertion ltsnled ( 𝜑 → ( 𝐴 <s 𝐵 ↔ ¬ 𝐵 ≤s 𝐴 ) )

Proof

Step Hyp Ref Expression
1 lesd.1 ⊢ ( 𝜑 → 𝐴 ∈ No )
2 lesd.2 ⊢ ( 𝜑 → 𝐵 ∈ No )
3 ltnles ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 <s 𝐵 ↔ ¬ 𝐵 ≤s 𝐴 ) )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 <s 𝐵 ↔ ¬ 𝐵 ≤s 𝐴 ) )