Metamath Proof Explorer


Theorem ltstrieq2

Description: Trichotomy law for surreal less-than. (Contributed by Scott Fenton, 22-Apr-2012)

Ref Expression
Assertion ltstrieq2 ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 = 𝐵 ↔ ( ¬ 𝐴 <s 𝐵 ∧ ¬ 𝐵 <s 𝐴 ) ) )

Proof

Step Hyp Ref Expression
1 ltsso ⊢ <s Or No
2 sotrieq2 ⊢ ( ( <s Or No ∧ ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) ) → ( 𝐴 = 𝐵 ↔ ( ¬ 𝐴 <s 𝐵 ∧ ¬ 𝐵 <s 𝐴 ) ) )
3 1 2 mpan ⊢ ( ( 𝐴 ∈ No ∧ 𝐵 ∈ No ) → ( 𝐴 = 𝐵 ↔ ( ¬ 𝐴 <s 𝐵 ∧ ¬ 𝐵 <s 𝐴 ) ) )