Metamath Proof Explorer


Theorem mdandyvrx6

Description: Given the exclusivities set in the hypotheses, there exist a proof where ch, th, ta, et exclude ze, si accordingly. (Contributed by Jarvin Udandy, 7-Sep-2016)

Ref Expression
Hypotheses mdandyvrx6.1 ⊢ ( 𝜑 ⊻ 𝜁 )
mdandyvrx6.2 ⊢ ( 𝜓 ⊻ 𝜎 )
mdandyvrx6.3 ⊢ ( 𝜒 ↔ 𝜑 )
mdandyvrx6.4 ⊢ ( 𝜃 ↔ 𝜓 )
mdandyvrx6.5 ⊢ ( 𝜏 ↔ 𝜓 )
mdandyvrx6.6 ⊢ ( 𝜂 ↔ 𝜑 )
Assertion mdandyvrx6 ( ( ( ( 𝜒 ⊻ 𝜁 ) ∧ ( 𝜃 ⊻ 𝜎 ) ) ∧ ( 𝜏 ⊻ 𝜎 ) ) ∧ ( 𝜂 ⊻ 𝜁 ) )

Proof

Step Hyp Ref Expression
1 mdandyvrx6.1 ⊢ ( 𝜑 ⊻ 𝜁 )
2 mdandyvrx6.2 ⊢ ( 𝜓 ⊻ 𝜎 )
3 mdandyvrx6.3 ⊢ ( 𝜒 ↔ 𝜑 )
4 mdandyvrx6.4 ⊢ ( 𝜃 ↔ 𝜓 )
5 mdandyvrx6.5 ⊢ ( 𝜏 ↔ 𝜓 )
6 mdandyvrx6.6 ⊢ ( 𝜂 ↔ 𝜑 )
7 1 3 axorbciffatcxorb ⊢ ( 𝜒 ⊻ 𝜁 )
8 2 4 axorbciffatcxorb ⊢ ( 𝜃 ⊻ 𝜎 )
9 7 8 pm3.2i ⊢ ( ( 𝜒 ⊻ 𝜁 ) ∧ ( 𝜃 ⊻ 𝜎 ) )
10 2 5 axorbciffatcxorb ⊢ ( 𝜏 ⊻ 𝜎 )
11 9 10 pm3.2i ⊢ ( ( ( 𝜒 ⊻ 𝜁 ) ∧ ( 𝜃 ⊻ 𝜎 ) ) ∧ ( 𝜏 ⊻ 𝜎 ) )
12 1 6 axorbciffatcxorb ⊢ ( 𝜂 ⊻ 𝜁 )
13 11 12 pm3.2i ⊢ ( ( ( ( 𝜒 ⊻ 𝜁 ) ∧ ( 𝜃 ⊻ 𝜎 ) ) ∧ ( 𝜏 ⊻ 𝜎 ) ) ∧ ( 𝜂 ⊻ 𝜁 ) )