Metamath Proof Explorer


Theorem mirimanoff

Description: Mirimanoff's paradox: The class of grounded sets is not a set. Here, a set x is grounded if there is no infinite membership-descending sequence of sets beginning with x . See Paragraph 1 of Quine p. 37 . (Contributed by Adrian Ducourtial, 11-Oct-2026)

Ref Expression
Hypothesis mirimanoff.1 ⊢ 𝑀 = { 𝑥 ∣ ¬ ∃ 𝑓 ( 𝑓 Fn ω ∧ ( 𝑓 ‘ ∅ ) = 𝑥 ∧ ∀ 𝑛 ∈ ω ( 𝑓 ‘ suc 𝑛 ) ∈ ( 𝑓 ‘ 𝑛 ) ) }
Assertion mirimanoff 𝑀 ∉ V

Proof

Step Hyp Ref Expression
1 mirimanoff.1 ⊢ 𝑀 = { 𝑥 ∣ ¬ ∃ 𝑓 ( 𝑓 Fn ω ∧ ( 𝑓 ‘ ∅ ) = 𝑥 ∧ ∀ 𝑛 ∈ ω ( 𝑓 ‘ suc 𝑛 ) ∈ ( 𝑓 ‘ 𝑛 ) ) }
2 rabab ⊢ { 𝑥 ∈ V ∣ ¬ ∃ 𝑓 ( 𝑓 Fn ω ∧ ( 𝑓 ‘ ∅ ) = 𝑥 ∧ ∀ 𝑛 ∈ ω ( 𝑓 ‘ suc 𝑛 ) ∈ ( 𝑓 ‘ 𝑛 ) ) } = { 𝑥 ∣ ¬ ∃ 𝑓 ( 𝑓 Fn ω ∧ ( 𝑓 ‘ ∅ ) = 𝑥 ∧ ∀ 𝑛 ∈ ω ( 𝑓 ‘ suc 𝑛 ) ∈ ( 𝑓 ‘ 𝑛 ) ) }
3 1 2 eqtr4i ⊢ 𝑀 = { 𝑥 ∈ V ∣ ¬ ∃ 𝑓 ( 𝑓 Fn ω ∧ ( 𝑓 ‘ ∅ ) = 𝑥 ∧ ∀ 𝑛 ∈ ω ( 𝑓 ‘ suc 𝑛 ) ∈ ( 𝑓 ‘ 𝑛 ) ) }
4 3 mirimanoffr ⊢ 𝑀 ∉ V