Metamath Proof Explorer


Theorem naddcld

Description: Closure law for natural addition. Deduction version. (Contributed by Scott Fenton, 10-Jun-2025)

Ref Expression
Hypotheses naddcld.1 ⊢ ( 𝜑 → 𝐴 ∈ On )
naddcld.2 ⊢ ( 𝜑 → 𝐵 ∈ On )
Assertion naddcld ( 𝜑 → ( 𝐴 +no 𝐵 ) ∈ On )

Proof

Step Hyp Ref Expression
1 naddcld.1 ⊢ ( 𝜑 → 𝐴 ∈ On )
2 naddcld.2 ⊢ ( 𝜑 → 𝐵 ∈ On )
3 naddcl ⊢ ( ( 𝐴 ∈ On ∧ 𝐵 ∈ On ) → ( 𝐴 +no 𝐵 ) ∈ On )
4 1 2 3 syl2anc ⊢ ( 𝜑 → ( 𝐴 +no 𝐵 ) ∈ On )