Metamath Proof Explorer


Theorem neii1

Description: A neighborhood is included in the topology's base set. (Contributed by NM, 12-Feb-2007)

Ref Expression
Hypothesis neifval.1 ⊢ 𝑋 = ∪ 𝐽
Assertion neii1 ( ( 𝐽 ∈ Top ∧ 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) ) → 𝑁 ⊆ 𝑋 )

Proof

Step Hyp Ref Expression
1 neifval.1 ⊢ 𝑋 = ∪ 𝐽
2 1 neiss2 ⊢ ( ( 𝐽 ∈ Top ∧ 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) ) → 𝑆 ⊆ 𝑋 )
3 1 isnei ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) ↔ ( 𝑁 ⊆ 𝑋 ∧ ∃ 𝑔 ∈ 𝐽 ( 𝑆 ⊆ 𝑔 ∧ 𝑔 ⊆ 𝑁 ) ) ) )
4 simpl ⊢ ( ( 𝑁 ⊆ 𝑋 ∧ ∃ 𝑔 ∈ 𝐽 ( 𝑆 ⊆ 𝑔 ∧ 𝑔 ⊆ 𝑁 ) ) → 𝑁 ⊆ 𝑋 )
5 3 4 biimtrdi ⊢ ( ( 𝐽 ∈ Top ∧ 𝑆 ⊆ 𝑋 ) → ( 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) → 𝑁 ⊆ 𝑋 ) )
6 5 impancom ⊢ ( ( 𝐽 ∈ Top ∧ 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) ) → ( 𝑆 ⊆ 𝑋 → 𝑁 ⊆ 𝑋 ) )
7 2 6 mpd ⊢ ( ( 𝐽 ∈ Top ∧ 𝑁 ∈ ( ( nei ‘ 𝐽 ) ‘ 𝑆 ) ) → 𝑁 ⊆ 𝑋 )