Metamath Proof Explorer


Theorem nfbi

Description: If x is not free in ph and ps , then it is not free in ( ph <-> ps ) . (Contributed by NM, 26-May-1993) (Revised by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 2-Jan-2018)

Ref Expression
Hypotheses nf.1 ⊢ Ⅎ 𝑥 𝜑
nf.2 ⊢ Ⅎ 𝑥 𝜓
Assertion nfbi Ⅎ 𝑥 ( 𝜑 ↔ 𝜓 )

Proof

Step Hyp Ref Expression
1 nf.1 ⊢ Ⅎ 𝑥 𝜑
2 nf.2 ⊢ Ⅎ 𝑥 𝜓
3 1 a1i ⊢ ( ⊤ → Ⅎ 𝑥 𝜑 )
4 2 a1i ⊢ ( ⊤ → Ⅎ 𝑥 𝜓 )
5 3 4 nfbid ⊢ ( ⊤ → Ⅎ 𝑥 ( 𝜑 ↔ 𝜓 ) )
6 5 mptru ⊢ Ⅎ 𝑥 ( 𝜑 ↔ 𝜓 )