Metamath Proof Explorer


Theorem nfs1f

Description: If x is not free in ph , it is not free in [ y / x ] ph . (Contributed by Mario Carneiro, 11-Aug-2016)

Ref Expression
Hypothesis nfs1f.1 𝑥 𝜑
Assertion nfs1f 𝑥 [ 𝑦 / 𝑥 ] 𝜑

Proof

Step Hyp Ref Expression
1 nfs1f.1 𝑥 𝜑
2 1 sbf ( [ 𝑦 / 𝑥 ] 𝜑𝜑 )
3 2 1 nfxfr 𝑥 [ 𝑦 / 𝑥 ] 𝜑