Metamath Proof Explorer


Theorem nfsb

Description: If z is not free in ph , then it is not free in [ y / x ] ph when y and z are distinct. See nfsbv for a version with an additional disjoint variable condition on x , z but not requiring ax-13 . (Contributed by Mario Carneiro, 11-Aug-2016) (Proof shortened by Wolf Lammen, 25-Feb-2024) Usage of this theorem is discouraged because it depends on ax-13 . Use nfsbv instead. (New usage is discouraged.)

Ref Expression
Hypothesis nfsb.1 𝑧 𝜑
Assertion nfsb 𝑧 [ 𝑦 / 𝑥 ] 𝜑

Proof

Step Hyp Ref Expression
1 nfsb.1 𝑧 𝜑
2 nftru 𝑥
3 1 a1i ( ⊤ → Ⅎ 𝑧 𝜑 )
4 2 3 nfsbd ( ⊤ → Ⅎ 𝑧 [ 𝑦 / 𝑥 ] 𝜑 )
5 4 mptru 𝑧 [ 𝑦 / 𝑥 ] 𝜑