Metamath Proof Explorer


Theorem nn0expcl

Description: Closure of exponentiation of nonnegative integers. (Contributed by NM, 14-Dec-2005)

Ref Expression
Assertion nn0expcl ( ( 𝐴 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) → ( 𝐴 ↑ 𝑁 ) ∈ ℕ0 )

Proof

Step Hyp Ref Expression
1 nn0sscn ⊢ ℕ0 ⊆ ℂ
2 nn0mulcl ⊢ ( ( 𝑥 ∈ ℕ0 ∧ 𝑦 ∈ ℕ0 ) → ( 𝑥 · 𝑦 ) ∈ ℕ0 )
3 1nn0 ⊢ 1 ∈ ℕ0
4 1 2 3 expcllem ⊢ ( ( 𝐴 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) → ( 𝐴 ↑ 𝑁 ) ∈ ℕ0 )