Metamath Proof Explorer


Theorem ofrfval

Description: Value of a relation applied to two functions. (Contributed by Mario Carneiro, 28-Jul-2014)

Ref Expression
Hypotheses offval.1 ⊢ ( 𝜑 → 𝐹 Fn 𝐴 )
offval.2 ⊢ ( 𝜑 → 𝐺 Fn 𝐵 )
offval.3 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
offval.4 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
offval.5 ⊢ ( 𝐴 ∩ 𝐵 ) = 𝑆
offval.6 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑥 ) = 𝐶 )
offval.7 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → ( 𝐺 ‘ 𝑥 ) = 𝐷 )
Assertion ofrfval ( 𝜑 → ( 𝐹 ∘r 𝑅 𝐺 ↔ ∀ 𝑥 ∈ 𝑆 𝐶 𝑅 𝐷 ) )

Proof

Step Hyp Ref Expression
1 offval.1 ⊢ ( 𝜑 → 𝐹 Fn 𝐴 )
2 offval.2 ⊢ ( 𝜑 → 𝐺 Fn 𝐵 )
3 offval.3 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
4 offval.4 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
5 offval.5 ⊢ ( 𝐴 ∩ 𝐵 ) = 𝑆
6 offval.6 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑥 ) = 𝐶 )
7 offval.7 ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐵 ) → ( 𝐺 ‘ 𝑥 ) = 𝐷 )
8 1 3 fnexd ⊢ ( 𝜑 → 𝐹 ∈ V )
9 2 4 fnexd ⊢ ( 𝜑 → 𝐺 ∈ V )
10 1 2 8 9 5 6 7 ofrfvalg ⊢ ( 𝜑 → ( 𝐹 ∘r 𝑅 𝐺 ↔ ∀ 𝑥 ∈ 𝑆 𝐶 𝑅 𝐷 ) )