Metamath Proof Explorer


Theorem oiiso

Description: The order isomorphism of the well-order R on A is an isomorphism. (Contributed by Mario Carneiro, 23-May-2015)

Ref Expression
Hypothesis oicl.1 ⊢ 𝐹 = OrdIso ( 𝑅 , 𝐴 )
Assertion oiiso ( ( 𝐴 ∈ 𝑉 ∧ 𝑅 We 𝐴 ) → 𝐹 Isom E , 𝑅 ( dom 𝐹 , 𝐴 ) )

Proof

Step Hyp Ref Expression
1 oicl.1 ⊢ 𝐹 = OrdIso ( 𝑅 , 𝐴 )
2 exse ⊢ ( 𝐴 ∈ 𝑉 → 𝑅 Se 𝐴 )
3 1 ordtype ⊢ ( ( 𝑅 We 𝐴 ∧ 𝑅 Se 𝐴 ) → 𝐹 Isom E , 𝑅 ( dom 𝐹 , 𝐴 ) )
4 3 ancoms ⊢ ( ( 𝑅 Se 𝐴 ∧ 𝑅 We 𝐴 ) → 𝐹 Isom E , 𝑅 ( dom 𝐹 , 𝐴 ) )
5 2 4 sylan ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝑅 We 𝐴 ) → 𝐹 Isom E , 𝑅 ( dom 𝐹 , 𝐴 ) )