Metamath Proof Explorer


Theorem oveq12

Description: Equality theorem for operation value. (Contributed by NM, 16-Jul-1995)

Ref Expression
Assertion oveq12 ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )

Proof

Step Hyp Ref Expression
1 oveq1 ⊢ ( 𝐴 = 𝐵 → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐶 ) )
2 oveq2 ⊢ ( 𝐶 = 𝐷 → ( 𝐵 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )
3 1 2 sylan9eq ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )