Metamath Proof Explorer


Theorem oveqan12rd

Description: Equality deduction for operation value. (Contributed by NM, 10-Aug-1995)

Ref Expression
Hypotheses oveq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
opreqan12i.2 ⊢ ( 𝜓 → 𝐶 = 𝐷 )
Assertion oveqan12rd ( ( 𝜓 ∧ 𝜑 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 opreqan12i.2 ⊢ ( 𝜓 → 𝐶 = 𝐷 )
3 1 2 oveqan12d ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )
4 3 ancoms ⊢ ( ( 𝜓 ∧ 𝜑 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )