Metamath Proof Explorer


Theorem par2catid

Description: A concrete category with two objects and two parallel nonidentity arrows. The two identity arrows both have raw value 2o ; their sources and targets distinguish them. The parallel arrows have raw values the empty set and 1o . (Contributed by Zhi Wang, 14-Sep-2026)

Ref Expression
Hypothesis par2catid.c ⊢ 𝐶 = { ⟨ ( Base ‘ ndx ) , 2o ⟩ , ⟨ ( Hom ‘ ndx ) , ( 𝑚 ∈ 2o , 𝑛 ∈ 2o ↦ if ( 𝑚 = 𝑛 , { 2o } , if ( ( 𝑚 = ∅ ∧ 𝑛 = 1o ) , 2o , ∅ ) ) ) ⟩ , ⟨ ( comp ‘ ndx ) , ( 𝑝 ∈ ( 2o × 2o ) , 𝑞 ∈ 2o ↦ ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) ) ) ⟩ }
Assertion par2catid ( 𝐶 ∈ Cat ∧ ( Id ‘ 𝐶 ) = ( 𝑦 ∈ 2o ↦ 2o ) )

Proof

Step Hyp Ref Expression
1 par2catid.c ⊢ 𝐶 = { ⟨ ( Base ‘ ndx ) , 2o ⟩ , ⟨ ( Hom ‘ ndx ) , ( 𝑚 ∈ 2o , 𝑛 ∈ 2o ↦ if ( 𝑚 = 𝑛 , { 2o } , if ( ( 𝑚 = ∅ ∧ 𝑛 = 1o ) , 2o , ∅ ) ) ) ⟩ , ⟨ ( comp ‘ ndx ) , ( 𝑝 ∈ ( 2o × 2o ) , 𝑞 ∈ 2o ↦ ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) ) ) ⟩ }
2 2oex ⊢ 2o ∈ V
3 2on ⊢ 2o ∈ On
4 ontr ⊢ ( 2o ∈ On → Tr 2o )
5 3 4 ax-mp ⊢ Tr 2o
6 dftr4 ⊢ ( Tr 2o ↔ 2o ⊆ 𝒫 2o )
7 5 6 mpbi ⊢ 2o ⊆ 𝒫 2o
8 df-3o ⊢ 3o = suc 2o
9 df-suc ⊢ suc 2o = ( 2o ∪ { 2o } )
10 8 9 eqtri ⊢ 3o = ( 2o ∪ { 2o } )
11 eqid ⊢ ( 𝑚 ∈ 2o , 𝑛 ∈ 2o ↦ if ( 𝑚 = 𝑛 , { 2o } , if ( ( 𝑚 = ∅ ∧ 𝑛 = 1o ) , 2o , ∅ ) ) ) = ( 𝑚 ∈ 2o , 𝑛 ∈ 2o ↦ if ( 𝑚 = 𝑛 , { 2o } , if ( ( 𝑚 = ∅ ∧ 𝑛 = 1o ) , 2o , ∅ ) ) )
12 eqid ⊢ ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) ) = ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) )
13 eqid ⊢ ( 𝑝 ∈ ( 2o × 2o ) , 𝑞 ∈ 2o ↦ ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) ) ) = ( 𝑝 ∈ ( 2o × 2o ) , 𝑞 ∈ 2o ↦ ( 𝑟 ∈ 3o , 𝑠 ∈ 3o ↦ ( 𝑟 ∩ 𝑠 ) ) )
14 2 2 7 10 11 12 13 1 parcatid ⊢ ( 𝐶 ∈ Cat ∧ ( Id ‘ 𝐶 ) = ( 𝑦 ∈ 2o ↦ 2o ) )