Metamath Proof Explorer


Theorem pncan3i

Description: Subtraction and addition of equals. (Contributed by NM, 26-Nov-1994)

Ref Expression
Hypotheses negidi.1 𝐴 ∈ ℂ
pncan3i.2 𝐵 ∈ ℂ
Assertion pncan3i ( 𝐴 + ( 𝐵𝐴 ) ) = 𝐵

Proof

Step Hyp Ref Expression
1 negidi.1 𝐴 ∈ ℂ
2 pncan3i.2 𝐵 ∈ ℂ
3 pncan3 ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( 𝐴 + ( 𝐵𝐴 ) ) = 𝐵 )
4 1 2 3 mp2an ( 𝐴 + ( 𝐵𝐴 ) ) = 𝐵