Description: Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | prlngin0.l | ⊢ 𝐿 = ( LineG ‘ 𝐺 ) | |
| prlngin0.p | ⊢ ∥ = ( parlnG ‘ 𝐺 ) | ||
| prlngin0.g | ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 ) | ||
| prlngin0.1 | ⊢ ( 𝜑 → 𝐴 ∥ 𝐵 ) | ||
| Assertion | prlngrcl2 | ⊢ ( 𝜑 → 𝐵 ∈ ran 𝐿 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | prlngin0.l | ⊢ 𝐿 = ( LineG ‘ 𝐺 ) | |
| 2 | prlngin0.p | ⊢ ∥ = ( parlnG ‘ 𝐺 ) | |
| 3 | prlngin0.g | ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 ) | |
| 4 | prlngin0.1 | ⊢ ( 𝜑 → 𝐴 ∥ 𝐵 ) | |
| 5 | eqid | ⊢ ( hlG ‘ 𝐺 ) = ( hlG ‘ 𝐺 ) | |
| 6 | 1 5 2 3 | brprlng | ⊢ ( 𝜑 → ( 𝐴 ∥ 𝐵 ↔ ( ( 𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿 ) ∧ ( 𝐴 = 𝐵 ∨ ( ∃ ℎ ∈ ran ( hlG ‘ 𝐺 ) ( 𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ ) ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) ) ) ) ) |
| 7 | 4 6 | mpbid | ⊢ ( 𝜑 → ( ( 𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿 ) ∧ ( 𝐴 = 𝐵 ∨ ( ∃ ℎ ∈ ran ( hlG ‘ 𝐺 ) ( 𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ ) ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) ) ) ) |
| 8 | 7 | simplrd | ⊢ ( 𝜑 → 𝐵 ∈ ran 𝐿 ) |