Metamath Proof Explorer


Theorem prlngrcl2

Description: Reverse closure for parallelism. (Contributed by Thierry Arnoux, 5-Jul-2026)

Ref Expression
Hypotheses prlngin0.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
prlngin0.p ⊢ ∥ = ( parlnG ‘ 𝐺 )
prlngin0.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
prlngin0.1 ⊢ ( 𝜑 → 𝐴 ∥ 𝐵 )
Assertion prlngrcl2 ( 𝜑 → 𝐵 ∈ ran 𝐿 )

Proof

Step Hyp Ref Expression
1 prlngin0.l ⊢ 𝐿 = ( LineG ‘ 𝐺 )
2 prlngin0.p ⊢ ∥ = ( parlnG ‘ 𝐺 )
3 prlngin0.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑉 )
4 prlngin0.1 ⊢ ( 𝜑 → 𝐴 ∥ 𝐵 )
5 eqid ⊢ ( hlG ‘ 𝐺 ) = ( hlG ‘ 𝐺 )
6 1 5 2 3 brprlng ⊢ ( 𝜑 → ( 𝐴 ∥ 𝐵 ↔ ( ( 𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿 ) ∧ ( 𝐴 = 𝐵 ∨ ( ∃ ℎ ∈ ran ( hlG ‘ 𝐺 ) ( 𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ ) ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) ) ) ) )
7 4 6 mpbid ⊢ ( 𝜑 → ( ( 𝐴 ∈ ran 𝐿 ∧ 𝐵 ∈ ran 𝐿 ) ∧ ( 𝐴 = 𝐵 ∨ ( ∃ ℎ ∈ ran ( hlG ‘ 𝐺 ) ( 𝐴 ⊆ ℎ ∧ 𝐵 ⊆ ℎ ) ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) ) ) )
8 7 simplrd ⊢ ( 𝜑 → 𝐵 ∈ ran 𝐿 )