Metamath Proof Explorer


Theorem reldmfrlm

Description: The domain of the free module function is a relation. (Contributed by SN, 24-Sep-2026)

Ref Expression
Assertion reldmfrlm Rel dom freeLMod

Proof

Step Hyp Ref Expression
1 df-frlm ⊢ freeLMod = ( 𝑟 ∈ V , 𝑖 ∈ V ↦ ( 𝑟 ⊕m ( 𝑖 × { ( ringLMod ‘ 𝑟 ) } ) ) )
2 1 reldmmpo ⊢ Rel dom freeLMod