Metamath Proof Explorer


Theorem relin1

Description: The intersection with a relation is a relation. (Contributed by NM, 16-Aug-1994)

Ref Expression
Assertion relin1 ( Rel 𝐴 → Rel ( 𝐴𝐵 ) )

Proof

Step Hyp Ref Expression
1 inss1 ( 𝐴𝐵 ) ⊆ 𝐴
2 relss ( ( 𝐴𝐵 ) ⊆ 𝐴 → ( Rel 𝐴 → Rel ( 𝐴𝐵 ) ) )
3 1 2 ax-mp ( Rel 𝐴 → Rel ( 𝐴𝐵 ) )