Metamath Proof Explorer
Description: Ring homomorphisms preserve subtraction. (Contributed by Jeff Madsen, 15-Jun-2011) (Revised by AV, 10-Jan-2025)
|
|
Ref |
Expression |
|
Hypotheses |
rhmsub.x |
⊢ 𝑋 = ( Base ‘ 𝑅 ) |
|
|
rhmsub.m |
⊢ − = ( -g ‘ 𝑅 ) |
|
|
rhmsub.n |
⊢ 𝑁 = ( -g ‘ 𝑆 ) |
|
Assertion |
rhmsub |
⊢ ( ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
rhmsub.x |
⊢ 𝑋 = ( Base ‘ 𝑅 ) |
| 2 |
|
rhmsub.m |
⊢ − = ( -g ‘ 𝑅 ) |
| 3 |
|
rhmsub.n |
⊢ 𝑁 = ( -g ‘ 𝑆 ) |
| 4 |
|
rhmghm |
⊢ ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) → 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) ) |
| 5 |
1 2 3
|
ghmsub |
⊢ ( ( 𝐹 ∈ ( 𝑅 GrpHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) ) |
| 6 |
4 5
|
syl3an1 |
⊢ ( ( 𝐹 ∈ ( 𝑅 RingHom 𝑆 ) ∧ 𝐴 ∈ 𝑋 ∧ 𝐵 ∈ 𝑋 ) → ( 𝐹 ‘ ( 𝐴 − 𝐵 ) ) = ( ( 𝐹 ‘ 𝐴 ) 𝑁 ( 𝐹 ‘ 𝐵 ) ) ) |