Metamath Proof Explorer


Theorem sbcco2

Description: A composition law for class substitution. Importantly, x may occur free in the class expression substituted for A . (Contributed by NM, 5-Sep-2004) (Proof shortened by Andrew Salmon, 8-Jun-2011)

Ref Expression
Hypothesis sbcco2.1 ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
Assertion sbcco2 ( [ 𝑥 / 𝑦 ] [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sbcco2.1 ⊢ ( 𝑥 = 𝑦 → 𝐴 = 𝐵 )
2 sbsbc ⊢ ( [ 𝑥 / 𝑦 ] [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝑥 / 𝑦 ] [ 𝐵 / 𝑥 ] 𝜑 )
3 1 equcoms ⊢ ( 𝑦 = 𝑥 → 𝐴 = 𝐵 )
4 dfsbcq ⊢ ( 𝐴 = 𝐵 → ( [ 𝐴 / 𝑥 ] 𝜑 ↔ [ 𝐵 / 𝑥 ] 𝜑 ) )
5 4 bicomd ⊢ ( 𝐴 = 𝐵 → ( [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 ) )
6 3 5 syl ⊢ ( 𝑦 = 𝑥 → ( [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 ) )
7 6 sbievw ⊢ ( [ 𝑥 / 𝑦 ] [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 )
8 2 7 bitr3i ⊢ ( [ 𝑥 / 𝑦 ] [ 𝐵 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 )