Metamath Proof Explorer


Theorem sbequivvOLD

Description: Obsolete version of sbequi as of 7-Jul-2023. Version of sbequi with disjoint variable conditions, not requiring ax-13 . (Contributed by Wolf Lammen, 19-Jan-2023) (New usage is discouraged.) (Proof modification is discouraged.)

Ref Expression
Assertion sbequivvOLD ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) )

Proof

Step Hyp Ref Expression
1 equeuclr ( 𝑥 = 𝑦 → ( 𝑧 = 𝑦𝑧 = 𝑥 ) )
2 1 imim1d ( 𝑥 = 𝑦 → ( ( 𝑧 = 𝑥𝜑 ) → ( 𝑧 = 𝑦𝜑 ) ) )
3 2 alimdv ( 𝑥 = 𝑦 → ( ∀ 𝑧 ( 𝑧 = 𝑥𝜑 ) → ∀ 𝑧 ( 𝑧 = 𝑦𝜑 ) ) )
4 sb6 ( [ 𝑥 / 𝑧 ] 𝜑 ↔ ∀ 𝑧 ( 𝑧 = 𝑥𝜑 ) )
5 sb6 ( [ 𝑦 / 𝑧 ] 𝜑 ↔ ∀ 𝑧 ( 𝑧 = 𝑦𝜑 ) )
6 3 4 5 3imtr4g ( 𝑥 = 𝑦 → ( [ 𝑥 / 𝑧 ] 𝜑 → [ 𝑦 / 𝑧 ] 𝜑 ) )