Metamath Proof Explorer


Theorem sbievwOLD

Description: Obsolete version of sbievw as of 24-Aug-2025. (Contributed by NM, 30-Jun-1994) (Revised by BJ, 18-Jul-2023) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Hypothesis sbievw.is ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
Assertion sbievwOLD ( [ 𝑦 / 𝑥 ] 𝜑𝜓 )

Proof

Step Hyp Ref Expression
1 sbievw.is ( 𝑥 = 𝑦 → ( 𝜑𝜓 ) )
2 sb6 ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) )
3 1 equsalvw ( ∀ 𝑥 ( 𝑥 = 𝑦𝜑 ) ↔ 𝜓 )
4 2 3 bitri ( [ 𝑦 / 𝑥 ] 𝜑𝜓 )