Metamath Proof Explorer


Theorem sbimdv

Description: Deduction substituting both sides of an implication, with ph and x disjoint. See also sbimd . (Contributed by Wolf Lammen, 6-May-2023) Revise df-sb . (Revised by Steven Nguyen, 6-Jul-2023)

Ref Expression
Hypothesis sbimdv.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
Assertion sbimdv ( 𝜑 → ( [ 𝑡 / 𝑥 ] 𝜓 → [ 𝑡 / 𝑥 ] 𝜒 ) )

Proof

Step Hyp Ref Expression
1 sbimdv.1 ⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) )
2 1 alrimiv ⊢ ( 𝜑 → ∀ 𝑥 ( 𝜓 → 𝜒 ) )
3 spsbim ⊢ ( ∀ 𝑥 ( 𝜓 → 𝜒 ) → ( [ 𝑡 / 𝑥 ] 𝜓 → [ 𝑡 / 𝑥 ] 𝜒 ) )
4 2 3 syl ⊢ ( 𝜑 → ( [ 𝑡 / 𝑥 ] 𝜓 → [ 𝑡 / 𝑥 ] 𝜒 ) )