Metamath Proof Explorer


Theorem sbtr

Description: A partial converse to sbt . If the substitution of a variable for a non-free one in a wff gives a theorem, then the original wff is a theorem. Usage of this theorem is discouraged because it depends on ax-13 . (Contributed by BJ, 15-Sep-2018) (New usage is discouraged.)

Ref Expression
Hypotheses sbtr.nf 𝑦 𝜑
sbtr.1 [ 𝑦 / 𝑥 ] 𝜑
Assertion sbtr 𝜑

Proof

Step Hyp Ref Expression
1 sbtr.nf 𝑦 𝜑
2 sbtr.1 [ 𝑦 / 𝑥 ] 𝜑
3 1 sbtrt ( ∀ 𝑦 [ 𝑦 / 𝑥 ] 𝜑𝜑 )
4 3 2 mpg 𝜑