Metamath Proof Explorer


Theorem sdomen2

Description: Equality-like theorem for equinumerosity and strict dominance. (Contributed by NM, 8-Nov-2003)

Ref Expression
Assertion sdomen2 ( 𝐴 ≈ 𝐵 → ( 𝐶 ≺ 𝐴 ↔ 𝐶 ≺ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 sdomentr ⊢ ( ( 𝐶 ≺ 𝐴 ∧ 𝐴 ≈ 𝐵 ) → 𝐶 ≺ 𝐵 )
2 1 ancoms ⊢ ( ( 𝐴 ≈ 𝐵 ∧ 𝐶 ≺ 𝐴 ) → 𝐶 ≺ 𝐵 )
3 ensym ⊢ ( 𝐴 ≈ 𝐵 → 𝐵 ≈ 𝐴 )
4 sdomentr ⊢ ( ( 𝐶 ≺ 𝐵 ∧ 𝐵 ≈ 𝐴 ) → 𝐶 ≺ 𝐴 )
5 4 ancoms ⊢ ( ( 𝐵 ≈ 𝐴 ∧ 𝐶 ≺ 𝐵 ) → 𝐶 ≺ 𝐴 )
6 3 5 sylan ⊢ ( ( 𝐴 ≈ 𝐵 ∧ 𝐶 ≺ 𝐵 ) → 𝐶 ≺ 𝐴 )
7 2 6 impbida ⊢ ( 𝐴 ≈ 𝐵 → ( 𝐶 ≺ 𝐴 ↔ 𝐶 ≺ 𝐵 ) )