Metamath Proof Explorer


Theorem sqrtm1

Description: The imaginary unit is the square root of negative 1. A lot of people like to call this the "definition" of _i , but the definition of sqrt df-sqrt has already been crafted with _i being mentioned explicitly, and in any case it doesn't make too much sense to define a value based on a function evaluated outside its domain. A more appropriate view is to take ax-i2m1 or i2 as the "definition", and simply postulate the existence of a number satisfying this property. This is the approach we take here. (Contributed by Mario Carneiro, 10-Jul-2013)

Ref Expression
Assertion sqrtm1 i = ( √ ‘ - 1 )

Proof

Step Hyp Ref Expression
1 1re 1 ∈ ℝ
2 0le1 0 ≤ 1
3 sqrtneg ( ( 1 ∈ ℝ ∧ 0 ≤ 1 ) → ( √ ‘ - 1 ) = ( i · ( √ ‘ 1 ) ) )
4 1 2 3 mp2an ( √ ‘ - 1 ) = ( i · ( √ ‘ 1 ) )
5 sqrt1 ( √ ‘ 1 ) = 1
6 5 oveq2i ( i · ( √ ‘ 1 ) ) = ( i · 1 )
7 ax-icn i ∈ ℂ
8 7 mulid1i ( i · 1 ) = i
9 4 6 8 3eqtrri i = ( √ ‘ - 1 )